Invoking deep thoughts: Integration

Why don't we add a constant of integration when integrating the second function while applying integration by parts? I'm searching for a perfectly logical answer

#Calculus #Integration

Note by Mayank Singh
5 years, 11 months ago

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Comments

Thanks for asking this question, I had the same one in my mind!

Swapnil Das - 5 years, 11 months ago

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Well I've reasoned something out... I'm waiting for some other replies

Mayank Singh - 5 years, 11 months ago

It will not affect the final answer. You can try it out yourself. The extra part, if you think there will be any, will get cancelled out at the end.

Sanchit Aggarwal - 5 years, 11 months ago

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What if I took different constants while integrating

P.S. You have to integrate g(x) twice while applying by parts

Mayank Singh - 5 years, 11 months ago

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Ofcourse you cannot take different constants. You are integrating only one function, no matter twice. It should be the same general constt., or no constant at all.

P.s. refer to the derivation of the formula once

Sanchit Aggarwal - 5 years, 11 months ago

What is "the second function"? On udv=uvvdu\int u \, dv = uv - \int v \, du, is the second function vv or vduv \, du?

Ivan Koswara - 5 years, 11 months ago

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The second function is 'dv', the function whose integral is 'v'

Sanchit Aggarwal - 5 years, 11 months ago
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