Is 2=1 Possible?

Once my teacher gave a proof of 2=1 which is as follow:

\( { 1 }^{ 2 }\quad =\quad 1\\ { 2 }^{ 2 }\quad =\quad 2\quad +\quad 2\\ { 3 }^{ 2 }\quad =\quad 3\quad +\quad 3\quad +\quad 3\\ .\\ .\\ .\\ .\\ .\\ { x }^{ 2 }\quad =\quad x\quad +\quad x\quad +\quad x\quad +\quad ........\quad upto\quad x\quad terms.\\ \\ Now\quad differentiating\quad both\quad sides\quad w.r.t\quad x,\\ 2x\quad =\quad 1\quad +\quad 1\quad +\quad 1\quad +\quad ........\quad upto\quad x\quad terms\\ ie,\quad 2x\quad =\quad x\\ \quad \quad \boxed { { 2\quad =\quad 1 } } \)

Now we were challenged to find the flaw in this proof ( Which we won )

Can you find the flaw in this proof ???

#Calculus

Note by Shravan Jain
7 years, 3 months ago

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1 vote

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Comments

Sincexcantakeonlypositiveintegralvalues(as1thterm,0thterm,0.5thtermdoesnotexists),thefunctionx2isdiscontinuousandthusisnondifferentiable. Since\quad x\quad can\quad take\quad only\quad positive\quad integral\quad values\quad \\ (as\quad { -1 }^{ th }\quad term,\quad { 0 }^{ th }\quad term,\quad { 0.5 }^{ th }\quad term\quad does\quad not\quad exists),\quad \\ the\quad function\quad { x }^{ 2 }\quad is\quad discontinuous\quad \\ and\quad thus\quad is\quad non\quad differentiable.

Shravan Jain - 7 years, 3 months ago

Thank you for posting this question.

You're trying to use the equality:

x2=x+x+...+x{x}^{2} = x + x + ... + x

You are trying to differentiate two functions. Let's see what we know about them.

Let f(x)=x2f(x)={x}^{2}. The domain for this function is clearly RR. And yeah when we differentiate we get f(x)=2xf'(x)=2x.

Let g(x)=x+x+...+xg(x)= x + x + ... + x (for the equality to be true x repeats in the sum exactly x times), then since a number can't repeat itself 2\sqrt { 2 } times the domain of this function is NN.

Now you differentiate. Tell me how you can calculate:

g(x0)=limxx0g(x)g(x0)xx0g'\left( { x }_{ 0 } \right) =\lim _{ x\rightarrow { x }_{ 0 } }{ \frac { g\left( x \right) -g\left( { x }_{ 0 } \right) }{ x-{ x }_{ 0 } } }

But you can't approach x0{ x } _ { 0 } on NN. You can only differentiate on intervals or RR.

More than this the differentiation gives you the slope of the tangent in x0{ x } _ { 0 }, but you can't have a slope to a function that's made of dots.

Even if we took ff defined on NN we still wouldn't have been able to differentiate it either.

So no, 2 isn't 1.

Adrian Neacșu - 7 years, 1 month ago

Well the you only differentiated the x's,the number of x's should also be differentiated as it is also a variable

Murlidhar Sharma - 7 years, 3 months ago

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Since this function is non differentiable , there is no question of differentiating the no. of x's

Shravan Jain - 7 years, 3 months ago

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Well,I dint even consider that lol

Murlidhar Sharma - 7 years, 3 months ago
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