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2 \times 3
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2^{34}
234
a_{i-1}
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Comments
yes...
When a charged particle enters a magnetic field perpendicular to it
then it experiences a force q[v×b] which is always perpendicular to the velocity
and hence the charged particle follows a circular motion at a constantspeed but at a varying velocity
In general whenever there is a force which is always perpendicular to the velocity vector then its component
along the velocity will be zero and the speed of the particle remains constant even if it is experiencing
Non Zero acceleration
Yes... If a body moves on a circular path with a uniform speed then due to the continuous change in the direction of the body, the acceleration is variable.
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
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or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
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to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
yes... When a charged particle enters a magnetic field perpendicular to it then it experiences a force q[v×b] which is always perpendicular to the velocity and hence the charged particle follows a circular motion at a constantspeed but at a varying velocity
In general whenever there is a force which is always perpendicular to the velocity vector then its component along the velocity will be zero and the speed of the particle remains constant even if it is experiencing Non Zero acceleration
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Thank you Ritesh.
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Ritesh you also pls join iit jee preparation club at google groups.
Yes... If a body moves on a circular path with a uniform speed then due to the continuous change in the direction of the body, the acceleration is variable.
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Pls Join iit jee preparation club at google groups.