It is a composite number!

$x$ and $y$ are both integers in the interval $[2,100]$ . Prove that there is always a positive integer $n$ , such that $x^{2^{n}}+y^{2^{n}}$ is a composite number.

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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

Now there is some n so that the expression becomes kp. We need to show that there exists n so that k > 1. Now there are some set of elements x^0,x^1...x^(d-1) modulo p. There are some set of elements 2^1,2^2...2^(f+1) modulo d so that f is the smallest number greater than or equal to 1 so that 2^(f+1)modulo d = (2^1)mod d. Note that n = f(g)+e, Where (2^n)mod(d) = (2^e)mod(d)=c. x^c mod p = h. This is an important observation: THE MODULUS OF x^2^n modulo p is entirely dependent on the modulus of n mod f. And similarly for y the modulus of y^2^n is entirely dependent on the modulus of n mod z. Now x^2^(fg+e)modp =h and y^2^(zw+t)modp = p - h (since for some n it is p). When f(g)+e=z(w)+t for and g and w (in the integers, left and right hand side are positive). The result is a multiple of p. Now given that this equation has a solution it has infinitely many solutions (euclidean algorithm) and so there are infinitely many values of n for which the result is a multiple of p. Now choose the smallest n so that the result is p. Choose a larger n which satisfies the linear diophantine equation. The result is greater than p but is a multiple of p and so is composite.

Siddharth Iyer - 5 years, 10 months ago

nice !

Aman Rajput - 5 years, 9 months ago

My solution is not really nice though I would like to see better solutions

Siddharth Iyer - 5 years, 9 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$