JEE CBT 2016 Question

What do you think should be the answer please answer asap.

The rate law for the reaction below is given by the expression k [A][B]

A+B -------> Product

If the concentration of B is increased from 0.1 to 0.3 mole, keeping the value of A at 0.1 mole, the rate constant will be :

(1)k

(2) k/3

(3) 3k

(4) 9k

#Chemistry

Easy Math Editor

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Comments

The rate 'constant' will not change.

Ameya Daigavane - 5 years, 1 month ago

Dilip Kumar - 5 years, 1 month ago

can you give the solution?

rahul gupta - 5 years, 1 month ago

The rate of the reaction will triple. However the rate constant will not change. Changing the concentration of the reactants will not affect the rate constant unless you change the temperature.

Ludho Madrid - 5 years, 1 month ago

Rate constant depend only on temperature not any other thing

AYUSH JAIN - 5 years ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$