JEE MAIN

If f(x) = x^4 + ax^3 + bx^2 + cx + d, and f(2)= 1, f(3) = 2, f(4) = 3, f(5) = 4, what is the value of a + b + c + d ? Please find it out as soon as possible. I am having problems in finding it out

#Algebra

Note by Eshan Abbas
6 years, 7 months ago

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Comments

Let g(x)=f(x)x+1 g(x) = f(x) - x + 1 .Then g(x)g(x) is of degree 4 4. And for x=2,3,4,5 x =2,3,4,5 , g(x)=0 g(x) = 0 .This implies 2,3,4,5 2,3,4,5 are the roots of g(x) g(x) .

Thus we can write g(x)=(x2)(x3)(x4)(x5) g(x) = (x-2)(x-3)(x-4)(x-5)

f(x)x+1=(x2)(x3)(x4)(x5) \Rightarrow f(x) - x + 1 = (x-2)(x-3)(x-4)(x-5)

x4+ax3+bx2+cx+dx+1=(x2)(x3)(x4)(x5) \Rightarrow x^4 + ax^3 + bx^2 + cx + d - x + 1 = (x-2)(x-3)(x-4)(x-5) .

Putting x=1 x = 1

14+a13+b12+c1+d1+1=(12)(13)(14)(15) \Rightarrow 1^4 + a*1^3 + b*1^2 + c*1 + d - 1 + 1 = (1-2)(1-3)(1-4)(1-5)

a+b+c+d=241=23 \Rightarrow a+b+c+d = 24-1 = 23 .

Siddhartha Srivastava - 6 years, 7 months ago

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I think that g(x) should be equal to f(x) - x + 1

Eshan Abbas - 6 years, 7 months ago

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Thanks. Corrected. Hopefully correct now.

Siddhartha Srivastava - 6 years, 7 months ago

thats what he got bro

Saurav Zuer - 6 years, 7 months ago
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