1]If median AD of a triangle ABC makes angle 30 degrees with side BC then \((\cot B-\cot C)^2\) is equal to?\[\]Options:6,9,12,15. \[\] 2]\[T_n=\sum_{r={2n}}^{3n-1}\dfrac{rn}{r^2+n^2},S_n=\sum_{r={2n+1}}^{3n}\dfrac{rn}{r^2+n^2}\].Then,\[T_n,S_n >\ or\ < \dfrac{\ln 2}{2}\].
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For number 1, this is what I thought of:
The way the question is worded implies that the result of (cotB−cotC)2 is always the same regardless of what the values of m∠B and m∠C are. You can use this to your advantage.
Let m∠ADC=30∘, and let m∠C=90∘. Now cotC=0, and you can use 30/60/90 triangle relationships to find cotB. I hope this helps!
The second one is based on a Jee 2008 question . I'll post the solution next week if you want me to. :)
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Yep... Its a JEE problem based on Riemann Sums....
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Best of luck for tmmrw!
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But how can we use that bcoz we don't know that n tends to infinity? And yes,best of luck!
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Yeah please do!
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Is the ans. Tn> ln2/2 and Sn<ln2/2 ?. You should see this video https://www.khanacademy.org/math/integral-calculus/indefinite-definite-integrals/riemann-sums/v/simple-riemann-approximation-using-rectangles