jmo question

Find a number which when divided by 10 leaves remainder 9, when divided by 8 leaves remainder 7, etc. down to where when divided by 2, it leaves remainder 1.

#AMANSHARMA

Easy Math Editor

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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

2519 is the smallest of such no.s

Raushan Sharma - 5 years, 11 months ago

119

Anil kumar - 5 years, 10 months ago

Let the no be A A = 10.b -1 A= 8.c -1 A= 6.d -1 A= 4e -1 A= 2f -1 Taking lcm of 10 , 8 , 6, 4, 2 we will get 120 120-1 =119

Ankit Lenka - 5 years, 9 months ago

839

Eric Christianson - 6 years, 8 months ago

119

Santosh Pothina - 6 years, 8 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$