Just for fun!!!

Is it really possible that 1=0??!!!

well, let's try-

let x=0

x^2=0.0=0

x^3=0.0.0=0

Now,

x^3-x^2=0-0=0

x^2(x-1)=0

Or,x-1=0

Or,x=1!!!

Can anyone explain how is it wrong??

Easy Math Editor

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Comments

till x^2(x-1) =0 everything is right but on next step there is mistake. if ab=0 , a or b is 0 .Here a=x^2,b=(x-1).We already have a=0 which results in (x-1) may or may not equal to zero.To make the equation correct,(x-1) not equal to zero

shaheed vh - 7 years, 4 months ago

$(x-1)$ is equal to $-1$ , not $0$ . This is because you multiplied the $x^3$ factor to get $0$ , meaning that $1\ne0$ .

Michael Diao - 7 years, 4 months ago

When $x^3 - x^2 = x^2(x - 1)$ you divided by zero.

Sharky Kesa - 7 years, 4 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$