Proof that SinA+SinBSinA−SinB+CosB−CosACosB+CosA=22Sin2A−1\frac {Sin A + Sin B}{Sin A - Sin B} + \frac{Cos B - Cos A}{Cos B + Cos A} = \frac{2}{2 Sin^2 A -1} SinA−SinBSinA+SinB+CosB+CosACosB−CosA=2Sin2A−12
Note by Avisek Agarwal 6 years, 11 months ago
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Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
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to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
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