kinematics

A motor car is going due north at a speed of 50km/h.it makes a 90degree left turn without changing the speed.The change in the velocity of the car is about

Easy Math Editor

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`2 \times 3`	$2 \times 3$
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Comments

When the car is going north, the velocity is +50j (assuming up is +j, right is +i in vector coordinates). When car takes left turn, it is moving west, so the velocity is -50i. Change is velocity is final velocity - initial velocity = (-50i - 50j)km/hr.

This should be your final answer. You have to consider direction also, since change in "velocity" is asked.

Ajay Maity - 7 years, 6 months ago

Nikhil Fastrack - 7 years, 1 month ago

MaryAm KhaleEq - 7 years, 6 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$