LC Impedance Conventions

It is fairly easy to derive AC impedance conventions for inductors and capacitors, starting with time-domain equations.

For the inductor:

v(t)=Lddti(t) v(t) = L \frac{d}{dt} i(t)

Take the Laplace transform:

V(s)=LsI(s) V(s) = L s I(s)

Substituting in s=jω s = j \omega .

V(jω)I(jω)=ZL=jωL \frac{V(j \omega)}{I(j \omega)} = Z_L = j \omega L

For the capacitor:

i(t)=Cddtv(t) i(t) = C \frac{d}{dt} v(t)

Take the Laplace transform:

I(s)=CsV(s) I(s) = C s V(s)

Substituting in s=jω s = j \omega .

V(jω)I(jω)=ZC=1jωC=jωC \frac{V(j \omega)}{I(j \omega)} = Z_C = \frac{1}{j \omega C} = - \frac{j}{\omega C}

This shows why inductors have +j + j impedance and capacitors have j - j impedance

Another way to show it is to examine the test signal sin(ωt) \sin(\omega t) . Suppose that this is the expression for the inductor current:

i(t)=sin(ωt)v(t)=Lddti(t)=ωLcos(ωt) i(t) = \sin(\omega t) \\ v(t) = L \frac{d}{dt} i(t) = \omega L \cos (\omega t)

We can see that for the inductor, the voltage is greater than the current by a factor ωL \omega L , and it leads by 90 degrees (agreeing with the +j + j ) term derived earlier.

Now examine the capacitor in the time domain:

v(t)=sin(ωt)i(t)=Cddtv(t)=ωCcos(ωt) v(t) = \sin(\omega t) \\ i(t) = C \frac{d}{dt} v(t) = \omega C \cos (\omega t)

We see that the voltage is smaller than the current by a factor ωC \omega C , and that the voltage lags the current by 90 degrees, agreeing with the transfer function derived earlier.

#ElectricityAndMagnetism

Note by Steven Chase
9 months, 2 weeks ago

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Comments

@Steven Chase Thanks.

Talulah Riley - 9 months, 2 weeks ago

@Steven Chase is there any other way to prove it, other than laplace transform.

Talulah Riley - 9 months, 2 weeks ago

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I have added a bit to the end

Steven Chase - 9 months, 2 weeks ago

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@Steven Chase Yeah Thanks.

Talulah Riley - 9 months, 2 weeks ago

Your knowledge of Alternating current is next level.
I feel very unconfident while solving Alternating current problems.

Talulah Riley - 9 months, 2 weeks ago

@Steven Chase Therefore i have started series of Alternating current problems.
Make sure to drop a solution.
Hope I am not disturbing you.
Thanks in advance.

Talulah Riley - 9 months, 2 weeks ago

@Steven Chase https://brilliant.org/problems/alternating-current-series-4/

Talulah Riley - 9 months, 2 weeks ago

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I'm not sure what the physical mechanism for that one is supposed to be. Do you have an idea?

Steven Chase - 9 months, 2 weeks ago

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@Steven Chase Yeah right now I got a YouTube channel where this problem is discussed.
Here is the video.

Talulah Riley - 9 months, 1 week ago

@Steven Chase Hello, Good Morning.
I have posted a new problem. Please check my answer is correct or not?
Thanks in advance.

Talulah Riley - 9 months, 2 weeks ago

@Steven Chase https://brilliant.org/problems/electromagnetic-induction-4/

Talulah Riley - 9 months, 2 weeks ago

@Steven Chase Good. Evening,Help me in this

Talulah Riley - 9 months, 2 weeks ago

@Steven Chase hello Good Afternoon,Try this problem
And share your views.

Talulah Riley - 9 months, 1 week ago

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Initially, the left capacitor has voltage V and the right capacitor has no voltage. Then after the switch opens, the system is subject to the following constraints.

1) The sum of the two capacitor voltages must be V
2) Since the capacitors are in series, and they have the same capacitance, the change in one capacitor's voltage must exactly match the change in the other capacitor's voltage.

There are three scenarios to consider then:

1) The capacitor voltages are exactly the same after switch opening as before switch opening
2) Both capacitors increase their voltages relative to before switch opening
3) Both capacitors decrease their voltages relative to before switch opening

Scenarios 2 and 3 can't happen without violating constraint #1. Therefore nothing happens, and no heat is dissipated.

Steven Chase - 9 months, 1 week ago

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@Steven Chase Your answer is correct but one thing which I have not understand properly is
“The capacitor voltages are exactly the same after switch opening as before switch opening”

Talulah Riley - 9 months, 1 week ago

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@Talulah Riley In other words, they don't change at all

Steven Chase - 9 months, 1 week ago

@Steven Chase do you have edited the note?

Talulah Riley - 8 months, 3 weeks ago

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It is the same as it was earlier

Steven Chase - 8 months, 3 weeks ago

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@Steven Chase You have very much knowledge of electrical engineering.
Nowadays I am feeling jealous with you. :)

Talulah Riley - 8 months, 3 weeks ago

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@Talulah Riley No worries. I have been doing this a long time

Steven Chase - 8 months, 3 weeks ago

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@Steven Chase @Steven Chase I was joking :). Just to make you feel better :)

Talulah Riley - 8 months, 3 weeks ago

@Steven Chase @Steven Chase Do you mean that, you are making people feel jealous from long time ??

Talulah Riley - 8 months, 3 weeks ago

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@Talulah Riley No, I've been studying electrical engineering for a long time

Steven Chase - 8 months, 3 weeks ago

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@Steven Chase @Steven Chase I know that, I was kidding you.

Talulah Riley - 8 months, 3 weeks ago
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