Lets say thanks to brilliant

Brilliant Problems are really very cool and they help us a lot to prepare for various competitive exams ...i have been using brilliant very less but yest solving the practice section and the problems have really helped me to improve a lot..especially the reading part of olympiad and "just for fun" section are awesome ....so i think for giving us such a help we all should thank brilliant...so all of you please comment your thank below

#Geometry #Combinatorics #Calculus #NumberThoery

Note by Raman Tejaswi
7 years, 1 month ago

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1 vote

  Easy Math Editor

This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

When posting on Brilliant:

  • Use the emojis to react to an explanation, whether you're congratulating a job well done , or just really confused .
  • Ask specific questions about the challenge or the steps in somebody's explanation. Well-posed questions can add a lot to the discussion, but posting "I don't understand!" doesn't help anyone.
  • Try to contribute something new to the discussion, whether it is an extension, generalization or other idea related to the challenge.
  • Stay on topic — we're all here to learn more about math and science, not to hear about your favorite get-rich-quick scheme or current world events.

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
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1. numbered
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[example link](https://brilliant.org)example link
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    # 4 spaces, and now they show
    # up as a code block.

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# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 2×3 2 \times 3
2^{34} 234 2^{34}
a_{i-1} ai1 a_{i-1}
\frac{2}{3} 23 \frac{2}{3}
\sqrt{2} 2 \sqrt{2}
\sum_{i=1}^3 i=13 \sum_{i=1}^3
\sin \theta sinθ \sin \theta
\boxed{123} 123 \boxed{123}

Comments

Well, I would like to thank my fellow Brilliantines before thanking Brilliant. Brilliant, of course gave a great platform for great minds to meet, but without people, a community is a void set. Thank you everybody!

Satvik Golechha - 7 years, 1 month ago

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:D

Finn Hulse - 7 years, 1 month ago

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@Finn Hulse , what is ":D"

Satvik Golechha - 7 years ago

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@Satvik Golechha It just is a smiley face. It means I'm happy and cheerful, or I've just heard a good joke. :D

Finn Hulse - 7 years ago

Brilliantine! That's a nice decoration. I'm a brilliantine! Thanks brilliant. Thanks Satvik.

Aji Karunakaran - 7 years, 1 month ago

If Brilliant didn't exist, we'd have to invent it! Thank you!

Richard Polak - 7 years, 1 month ago

Thank you so much Brilliant! :D

Finn Hulse - 7 years, 1 month ago

THANKS

swapnil rajawat - 7 years, 1 month ago

Thanks brilliant and stuff members, you really help us

Mardokay Mosazghi - 7 years ago

Thank you brilliant! :D

Arya Baskara - 7 years, 1 month ago

Thanks to Brilliant!

Ahmad Naufal Hakim - 7 years, 1 month ago

Thank you Brilliant for changing my mathematical life. Without you, I wouldn't be as well as I am right now.

Sharky Kesa - 7 years ago

Thanks to brilliant stuff and members for their immense help!

Anik Mandal - 7 years ago

Thanks to brilliant

Raman Tejaswi - 7 years, 1 month ago
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