Lets use a Super-Calculator ! e^{\pi\sqrt{163}}= Integer ?

To see if you qualify :- $(\text{Irrational})^{\text{Irrational}}=\text{Irrational} \\ \text{A. True} \quad \text{B. False} \quad \text{C. Unpredictable !}$

Ok. Fine ! Now what will be your reaction if you come out to know that $e^{\pi\sqrt{163}}$ is an integer. (waiting for your GIFs about your reaction). Don't you feel it strange that three irrational numbers $e$ , $\pi$ and $\sqrt{163}$ can be combined to form an integer ?

In fact, the Indian Mathematician Srinivasa Ramanujan (1888-1920) first conjectured that $e^{\pi\sqrt{163}}$ was an integer. He felt he found its value to be : $262537412640768743.999.......$

In 1972, computers had carried it out to 2 million places of 9's, but to be an integer one must know it repeats forever.

So, if 9 repeats forever, then $e^{\pi\sqrt{163}}$ will be equal to $262537412640768744$

Now let me know if you're enough convinced to try to figure out its exact value !!!

Leave your amazing comments & ideas here. and Keep Exploring the Universe of Mathematics.

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Comments

I am astonishment! I NEVER knew that $\displaystyle { e }^{ \pi \sqrt { 163 } }$ could be an integer. I have so much to learn about mathematics. This is a perfect example of how simple intuition leads you astray. Can't trust your intuition, ya gotta do the math and work out all those decimals after the $...8743.999...$

Meanwhile, no, it's not true that ${ \left( Irrational \right) }^{ Irrational }=Irrational$ is always true. To see why, let $x$ be an unknown. Then we solve for $x$ the equation ${ x }^{ x }=2\quad$ or any other such rational number besides $2$ . Then in nearly all cases, $x$ is not rational.

For a fascinating insight into this factoid, look up "Heegner Numbers" and check out Ramanujan's contribution to it.

Michael Mendrin - 6 years ago

I am astonishment! I NEVER knew that eπ163√ could be an integer.

Is this sarcasm? Because it isn't an integer and Poe's law.

Siddhartha Srivastava - 6 years ago

Siddhartha, that was pretty cool, this is the first time I've heard of Poe's Law. It's right on target! Let me offer a corollary to Poe's Law, which is that no matter how outrageous or silly a politician's or pundit's statements may be, there will always be lots of people that believe them wholeheartedly.

Still, Heegner's numbers, to me, is a pretty fascinating subject. Heegner Number

Also here too Heegner Number

I really like the lineup of this very finite sequence of nine Heegner numbers

$1, 2, 3, 7, 11, 19, 43, 67, 163$

@Michael Mendrin – What's the proof that there are only 9 of them?

Kartik Sharma - 6 years ago

@Kartik Sharma – Look up Stark-Heegner Theorem What's interesting is that Carl Gauss as far back in the 19th century had conjectured that there would only be a finite number of them. But it took about a century to prove it, and another half century for other mathematicians to finally accept Heegner's 1952 proof of it, after it was upgraded by Stark in 1969. This has had a long history with a number of luminaries having worked on it, almost like Fermat's Last Theorem.

@Michael Mendrin – That's interesting!

Very interesting

Arunesh Kumar - 5 years, 11 months ago

Wow!!

Akshat Sharda - 5 years, 9 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Lets use a Super-Calculator ! eπ163=e^{\pi\sqrt{163}}=eπ163​= Integer ?

Comments

Lets use a Super-Calculator ! $e^{\pi\sqrt{163}}=$ Integer ?