Light and Time... doesn't match

Light is emitted by matter which is at a speed lower than cc. Also, Light travels only at a speed c=299792458c=299792458 m/s. Also, Acceleration a=ΔvΔta=\frac{\Delta v}{\Delta t}. as Light can only travel at cc, light must achieve cc in Δt=0\Delta t=0. if a=Δv0a=\frac{\Delta v}{0} then a=a=\infty.Will it happen in this universe? or is there any medium in this universe? I request everyone to comment on this... Please Don't Ignore... Even if yours or my answer is wrong,comment on this...

Note by Fahad Shihab
7 years, 8 months ago

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Comments

Your assumption that Δt=0\Delta t=0 is right but you also assume that Δv0\Delta v \neq 0 which is not right. Actually Δv\Delta v is also equal to 00. This is because the initial and final speed are same and equal to cc.

Shubham Srivastava - 7 years, 8 months ago

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how? Light is emitted by matter which is travelling at speeds below cc. So, if it wants to go at cc, a change of velocity must occur. so,Δv0\Delta v\neq0.

Fahad Shihab - 7 years, 8 months ago

Rule of Mathematics, In Shape ab\frac{a}{b} , with b \neq 0, so there exists this possibility ! Δ\Deltatt \neq 0

Gabriel Merces - 7 years, 8 months ago

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in relativity, it is said that light can't travel at a speed lower than cc

Fahad Shihab - 7 years, 8 months ago

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It has to be a time for less than Be, After All Denominator must be \neq of 0

Alex Dias - 7 years, 8 months ago

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@Alex Dias that's why i am saying that even light can travel at speeds lower than cc

Fahad Shihab - 7 years, 8 months ago

Photons can only travel at a speed of cc in which beforehand, for instance when emitted from a atom; they simply didn't exist in the form of a photon. Photons theoretically have no mass as they do not interact with the Higgs field; hence cannot be accelerated.

Joel Jablonski - 7 years, 8 months ago

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OK. so, if it didn't exist in the form of a photon, it must have a travelling speed, that is c=299792458ms1c=299792458ms^{-1} and according to my knowledge, a=ΔvΔta=\frac{\Delta v}{\Delta t} as acceleration is a funcion of time, not mass. So, even if its mass is zero, it should have an acceleration. Can't it be?

Fahad Shihab - 7 years, 8 months ago

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I understand where you are coming from and I agree that acceleration is a function of the time, but it is only a representation. When the time 0 the velocity is already c and it did not start from a velocity of 0, it simply didn't exist in the form of a photon as I previously said. The travelling speed that you are talking about was just a form of energy that was suddenly converted into a photon, it didn't exactly have a 'speed' more like a potential.

The acceleration of a particle is not determined by the time, it is determined by its mass or the Higgs field. I haven't studied general relativity in depth though seeming as the photon does not interact with the Higgs field, it can not change its speed. Hence, the acceleration of the photon is a=ΔvΔta=\frac{Δv}{Δt} where change in velocity is 0, hence acceleration must always be 0 no matter what time, even at t=0.

Joel Jablonski - 7 years, 8 months ago

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@Joel Jablonski So, physically, light isn't visible to us. That means it is a wave and photons are imaginary. Then what is the reason for self propagation of light?

Fahad Shihab - 7 years, 8 months ago

Now another news... check this out!

Fahad Shihab - 7 years, 8 months ago

cc, is the speed of light in a vaccum, light doesn't slow down (de-accelerate), it just travels slower in a different medium. End of story.

Yong See Foo - 7 years, 8 months ago

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i am talking about light in a vacuum. Not mediums.

Fahad Shihab - 7 years, 8 months ago
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