1000 wine bottles were ordered for a feast by a king. 4 days before the feast, a person was caught mixing poison in a wine bottle, it is known that poison is present in only one wine bottle. King has 10 expendable workers, which he can order to drink wine. Now by using only those 10 people how can you separate that poisonous wine bottle, given that it takes 3 days for poison to kill a person.
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I am familiar with this puzzle. The solution uses binary mapping.
Flag each bottle with an unique 10 digit binary representation, As 1000<210, such representation is possible. For example,
1stbottle will be flagged as 0000000001 2ndbottle will be flagged as 0000000010 3rdbottle will be flagged as 0000000011 . . 1000thbottle will be flagged as 1111101000
Let the workers be A1,A2,A3,A4,A5,A6,A7,A8,A9 and A10
And each binary representation represents an unique drinking combination. For example the 3rd bottle represents,
∥∥∥∥A10A20A30A40A50A60A70A80A91A101∥∥∥∥
means only A9 and A10 will drink the 3rd bottle.
Another example, 1000 th bottle represents
∥∥∥∥A11A21A31A41A51A60A71A80A90A100∥∥∥∥ means A1,A2,A3,A4,A5 and A7 will drink the 1000 th bottle.
And after 3 days we can uniquely determine which bottle is poisoned, observing which workers die. For example, If A1,A2,A3,A4,A6,A8 and A10 die after 4 days, this will represent,
∥∥∥∥A11A21A31A41A50A61A70A81A90A101∥∥∥∥
means the 11110101012=98110 th bottle is poisoned
can't we ask the person who was mixing the poison????? just having fun!
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hehe, nice try, i should mention that all the bottles look exactly identical! so even he wont be able to tell that
1000 has 10 digits of binner. So we can separate that poisonous bottle with 10 person