Prove that dndxn∣x=0xn×nx=n!\left.\dfrac{d^n}{dx^n}\right|_{x=0}x^n\times n^x=n!dxndn∣∣∣∣x=0xn×nx=n! for all positive integer n.n.n.
Find, with proof, dndxnxn1−x.\dfrac{d^n}{dx^n}\dfrac{x^n}{1-x}.dxndn1−xxn.
Find, with proof, dndxnxn−1logx.\dfrac{d^n}{dx^n}x^{n-1}\log x.dxndnxn−1logx.
Note by Trevor B. 6 years, 9 months ago
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Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
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to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
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