maths so...

Which type of equation is this? And how many solutions it has? x+x=x

#Equations

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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

It is a linear equation because the highest power in the equation is 1. This is how you solve it: x+x=x x+x-x= x-x (you are doing the same thing to both sides of the equation so it stays the same) x=0 Thus the only solution to the equation is x=0.

A Former Brilliant Member - 6 years, 1 month ago

Can the solution not be infinite?I mean x=infinite.

Siddharth Singh - 6 years, 1 month ago

i dont think so... infinite isnt really a number so to speak, it is the idea of endlessness

A Former Brilliant Member - 6 years, 1 month ago

@A Former Brilliant Member – What do you think about? x+1=x? :)

Siddharth Singh - 6 years, 1 month ago

@Siddharth Singh – x+1-x=x-x, so 1 =0 This is false so the equation has no solution. Note that infinity is not a real number so it isnt a solution.

A Former Brilliant Member - 6 years, 1 month ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$