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This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
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2^{34}
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Comments
Is this question asked by your sir or what.This question was also asked by my friends in school.
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No, i go through this question while surfing on Internet
I tried this... But finally i got so many equations... Which were very complex
Here we go, an=an−1+1/an−1
Squaring both sides: an2=an−12+1/an−12+2
So, if we remove the term: 1/an−12 from RHS
Then, we can say that: an2>an−12+2
Therefore, applying a=1,2,3..till a75 and a1=1 a22>3 a32>5 .... .... ... Series is 2n−1
Therefore, a752>149 a75>12
Now, lets do another part: an2=an−12+1/an−12+2
As, we know that : Maximum value of 1/an−12=1 Therefore, if we remove this and add 1 then, we can say that: an2≤an−12+3
Note that equals to sign will be for n=2 only
Now, a22≤4 a32<7 a42<10 ... .... ..... Series is 3n-2 type:
Therefore, a752<223 a75<15
Hence, #12<a75<15
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Good solution
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Thanks :)
This question's solution can be found here
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Sorry but.... Solution is not there.. Check it again plz
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Dont worry, I will try to add a solution there