The above problem appeared in JEE- Advanced 2014 paper-1. Please try it before joining the discussion.
The answer given in the official key, and everywhere else is . Here is a solution:
But I believe that the answer should be . In the solutions released by coaching institutes, they have made an unsubstantiated assumption that the maximum error in measuring the length is equal to Least count of the Vernier scale. I think this is wrong. The problem clearly states that two independent observations are made. This must imply that the maximum error in each observation is least count. And hence, it follows that the maximum error in the difference of the readings is two least counts.
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
...\]
to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
@Mvs Saketh @Ronak Agarwal @Shashwat Shukla @Azhaghu Roopesh M @Krishna Sharma @Tanishq Varshney @Rohit Shah @Nishu sharma @Kushal Patankar
Log in to reply
I have found out the reason, and it seems that this question is right and I was wrong. We have to assume that the error in the first reading is zero as they have given that the Vernier scale division exactly coincides with a main scale division.
Log in to reply
Error analysis, Vernier Callipers are something I have not understood till now.
look at the resonance tube problem (multiple correct choice question) , do you think it is correct? the solution assumes that the resonance tube is an open tube (on one end)
however, the question says that there is a different gas in the tube, (not air), wont the gas escape if the tube is open , or is the whole lab filled with argon/neon/etc . hence i assumed that it was closed and attempted, only to realise later that we had to assume it was open, but doesnt make sense right
Log in to reply
A student is performing an experiment using a resonance column and a tuning fork of frequency 244𝑠𝑠−1. He is told that the air in the tube has been replaced by another gas (assume that the column remains filled with the gas). If the minimum height at which resonance occurs is (0.350±0.005) m , the gas in the tube is...
Log in to reply
best of luck
Log in to reply
Log in to reply
Log in to reply
Log in to reply
so just, doing this and that, i am pretty confident of maths and physics though, lesser problems, no clumsiness or amiguity and sufficient rough space are some things i really love about JEE advanced
Log in to reply
Log in to reply
in 2013 paper, it was hard, but the hard questions were solvable mostly through logic , whereas no matter how much logic you use, u cant even guess what xenate ion forms upon excess heating
but yet, we have to face however it is, and hence i have practiced and didnt leave out anything, Now i just wanna face it, and the slight fear i have just makes want to talk to people and say best of luck to everyone xD
Log in to reply
Log in to reply
Log in to reply
By the way are you comfortable with matrices.
Log in to reply
Log in to reply
My analytical skills are good ( Thinking in a striaght forward manner), my logical skills are pretty weak. I have a low IQ you can say.
Log in to reply
well, but you would still prefer logic questions in chem as compared to p-block questions that you wont happen to remember i think ?
Log in to reply
I hate rote chemistry.
Log in to reply
Log in to reply