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We know that (a+b)(mod m)=a(mod m)+b(mod m) and (ab)(mod m)=a(mod m) x b(mod m)
after knowing this it is a child's play.
50=1(mod 7)
that implies 50^n=1(mod 7) now keep that aside
48=-1(mod 7)
and 99=1(mod 7)
that implies 99^(3n-1)=1(mod 7)
that implies [99^(3n-1) x 48]=-1(mod 7)
Adding both these equations we get 50^n +[48 x 99^(3n -1)]=0(mod 7)
done done done dunna done.
P.S:THE LAST REMARK WILL ONLY BE UNDERSTOOD BY INDIANS.
I can understand it , but ten again, I am Indian. Me re ko patha ha hindi likin me re pas nahi ha hindi keyboard. That's me writing hindi, hope you can understand.
@Sharky Kesa
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I used the google translate, that is to input hindi there we have handwritten or even phonetic keyboard. btw i have a software too, it's called "BarahaPad" ,almost all indian languages can be typed by it..
@Aditya Raut
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In how many things are you so much what? I don't get what you mean by expertise attainer. I live in a very English background. If some sentence doesn't make sense to me, there's probably something wrong. BTW, attainer isn't a word.
@Sharky Kesa
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Haha we had that named section in our PACE booklets, it's the exercise which is the toughest in the whole book :P
By saying to you i meant simply "expert"
@Aditya Raut
–
I am an expert mainly in math and science (though not really). Calvin Lin is an expert at math. I am nowhere near him. I am alright in Hindi, but exceptional in English. I am above average in sport. Above national average in endurance. But yeah, I am a all-rounder you could say.
@Krishna Ar
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in maths particularly number theory i learned it all by myself mainly from brilliant.but other math topics were taught to me by my father.in science i am 0.
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
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Comments
Modulo challenge is child's play by Induction....
img
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Yes, I have it relatively low levelled. I want people to use modulo. I already know there is a solution using induction.
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I know you know but what i wanted to know is whether you know what the person in image knows about what you know ,know it ?
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50n+48×993n−1≡1n+−1×13n−1≡0(mod7)
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We know that (a+b)(mod m)=a(mod m)+b(mod m) and (ab)(mod m)=a(mod m) x b(mod m) after knowing this it is a child's play. 50=1(mod 7) that implies 50^n=1(mod 7) now keep that aside 48=-1(mod 7) and 99=1(mod 7) that implies 99^(3n-1)=1(mod 7) that implies [99^(3n-1) x 48]=-1(mod 7) Adding both these equations we get 50^n +[48 x 99^(3n -1)]=0(mod 7) done done done dunna done. P.S:THE LAST REMARK WILL ONLY BE UNDERSTOOD BY INDIANS.
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I can understand it , but ten again, I am Indian. Me re ko patha ha hindi likin me re pas nahi ha hindi keyboard. That's me writing hindi, hope you can understand.
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wow in never knew that u were INDIAN .PRETTY SURPRISING!!
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Very good solution..I too had the same one..."The last comment was not really guess-able"...ELucidate?
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Done dunna done.... is actually " डन डना डन " which is synonym for a ecstatic way of saying "it's done"
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@Sharky Kesa in how many things are you so much expertise attainer !!!
Oh my goddd !!!!!Log in to reply
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@Adarsh Kumar -You a telugu?
Wow! It did ring a bell but yeah..we Southies aren't much used to it :pLog in to reply
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yeah sorry i posted it in a haste.
We will show that 50n+48×993n−1≡0(mod7)
We have 50≡1(mod7), 48≡−1(mod7), and 99≡1(mod7)
Then, 50n+48×993n−1≡1n+(−1)×13n−1≡0(mod7)