A square ABCD has E,F,G are the midpoints of AD,DC,AC. GF intersects AC at H. Prove EH⊥BH.
A square ABCD has E,F,G,H lies on AB,BC,CD,AD so that AE=BF=CG=HD. Prove EG⊥HF.
A rectangle ABCD has BH⊥AC. K,E are the midpoints of AH,CD. Prove BK⊥KE.
Acute △ABC with orthocenter H, M,N lies on BH,CH so that ∠AMC=∠ANB=90°. Prove that AM=AN.
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2) △AEH,△BFE,△CGF,△DHG are all congruent.Hence, EF=FG=GH=HE which implies EFGH is a rhombus whose diagonals intersect at right angles.