Need help!

Q:-A moving car possesses average velocities of 5 m/s , 10 m/s and 15 m/s in the 1st, 2nd and 3rd seconds respectively. What is the total distance it covers in these 3 seconds?

Hi guys! I came across this question today, and I had no idea on how to solve it. Kindly help

Easy Math Editor

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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

Is the answer 30m???

Naman Kapoor - 6 years ago

Yes It is.

A Former Brilliant Member - 6 years ago

Hi Mehul , I think we need to use the formula $Average \ speed \ = \dfrac{Distance \ covered}{time \ taken}$ which gives the answer as $30m$ .

Nihar Mahajan - 6 years ago

@Swapnil Das @Nihar Mahajan (< Genius) @Sravanth Chebrolu @Kalash Verma Please Help!

Mehul Arora - 6 years ago

I have the same opinion as others, do you know the correct answer?

Sravanth C. - 6 years ago

Hi everyone! Thanks for the help! :D The answer is indeed 30. It just didn't strike me at that time :P

Mehul Arora - 6 years ago

Come online :3

Nihar Mahajan - 6 years ago

Okay. Wait.

Mehul Arora - 6 years ago

@Mehul Arora – :3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3:3

Nihar Mahajan - 6 years ago

Hi Mehul! How was your exam today?

Anik Mandal - 6 years ago

Really Sorry for a late reply, BTW the answer is 30 m.

Swapnil Das - 6 years ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$