Need help

I was reading a math book that says that the function below is less or equal to 3. Why is that?

2sin2x+22sin2x \Large 2^{\sin^2 x} + \dfrac2{2^{\sin^2 x}}

#Geometry

Note by Yossi Levi
4 years, 1 month ago

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Comments

Let f(x)=2sin2x+22sin2x \large f(x) = 2^{\sin^2 x} + \dfrac{2}{2^{\sin^2 x}}

2sin2x+2cos2x \large \Rightarrow 2^{\sin^2 x}+2^{\cos^2 x}

which has a maximum value of 3 3, equality at x=π2+nπ x=\frac{\pi}{2} + n\pi or x=nπ x = n\pi

where n n is a whole number.

Rahil Sehgal - 4 years, 1 month ago
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