Hi , I was trying out one of the IMO 1984 problems :
If \(x,y\) and \(z\) are non-negative real numbers such that \( x+y+z=1\) , prove the following inequality
xy+yz+zx−2xyz≤277
My approach :
Using the identities:
1.x3+y3+z3−3xyz=(x+y+z)(x2+y2+z2−xy−yz−zx)
2.(x+y+z)2=x2+y2+z2+2xy+2yz+2zx
The given inequality can be rewritten as :
2(x3+y3+z3)−23(x2+y2+z2)+21≥92
Consider the following function:
f(t)=2t3−23t2+61
The above function becomes convex for t ≥41
So, using Jensen's inequality on a,b and c
3f(a)+f(b)+f(c)≥f(31)
We get,
2(x3+y3+z3)−23(x2+y2+z2)+21≥2/9
So, I have proved the inequality . I want to confirm if my approach is correct. I think that it is not the complete proof as this proof included only those x,y and z which are greater than 41 . I do not have the proof that an yet lower value cannot be achieved when i consider all the x,y and z which range from 0 to 1.
#Algebra
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@Calvin Lin , @Chew-Seong Cheong, @Daniel Liu ,@Pi Han Goh can u please help me out with this .
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Try homogenizing the inequality.