Need help with inequality!!!

This problem seems so simple, but I cannot prove it:

a,b,c>0a,b,c>0.Prove that:

(a2+2)(b2+2)(c2+2)9(ab+bc+ca)(a^2+2)(b^2+2)(c^2+2)\geq 9(ab+bc+ca)

I tried all sorts of inequalities, but they didn't work.I reduced it to proving

(x+2)(y+2)(z+2)9(x+y+z)(x+2)(y+2)(z+2)\geq9(x+y+z), but I cannot prove that neither.

#Algebra #HelpMe! #Inequality #Pleasehelp

Note by Bogdan Simeonov
7 years ago

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1 vote

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Comments

Hi Bogdan, This question is from APMO exam. You can find the solutions here But, I can add a another solution with some trignometry here. We choose A,B,CA,B,C such that a=2tanAa=\sqrt{2}tanA, b=2tanBb=\sqrt{2}tanB,c=2tanCc=\sqrt{2}tanC. Now, by using 1+tan2x=1cos2x1+tan^{2}x=\frac{1}{cos^2x}, We get 49cosAcosBcosC(cosAsinBsinC+sinAcosBsinC+sinAsinBcosC)\frac{4}{9}≥cosAcosBcosC(cosAsinBsinC+sinAcosBsinC+sinAsinBcosC), Which is same as proving 49cosAcosBcosC(cosAcosBcosCcos(A+B+C))\frac{4}{9}≥cosAcosBcosC(cosAcosBcosC-cos(A+B+C)). Now, we have some "BAD LOOKING" Trignometric terms. So lets find a way to cancel them out. OK, then letting y=A+B+Cy=A+B+C. Now bu Simple AM-GM, We Get cosAcosBcosC(cosA+cosB+cosC3)3cos3ycosAcosBcosC≤(\frac{cosA+cosB+cosC}{3})^3≤cos^3y. Thus, Finally, we are left to show that 49cos3y(cos3ycos(3y))\frac{4}{9}≥cos^3y(cos^3y-cos(3y)). Now, by very easy simplification , we need to show 427cos4y(1cos2y)\frac{4}{27}≥cos^4y(1-cos^2y), Which follows from simple AM-GM As (cos2y2.cos2y2.(1cos2y))1313(cos2y2+cos2y2+(1cos2y))=13(\frac{cos^2y}{2}.\frac{cos^2y}{2}.(1-cos^2y))^{\frac{1}{3}}≤\frac{1}{3}(\frac{cos^2y}{2}+\frac{cos^2y}{2}+(1-cos^2y))=\frac{1}{3}. And the equality holds here at a=b=c=1a=b=c=1

Dinesh Chavan - 7 years ago

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Thanks for the quick response!

Bogdan Simeonov - 7 years ago

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Ok, Hope you might have cleared ur doubts

Dinesh Chavan - 7 years ago

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@Dinesh Chavan Why are your comments down voted?Also, at the end of the discussion someone mentioned a pretty strong result and didn't prove it.Any ideas?

Bogdan Simeonov - 7 years ago

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@Bogdan Simeonov Wait, I will try now,, For the downvotes, I know who did it, Nevermind :)

Dinesh Chavan - 7 years ago

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@Dinesh Chavan Ok :D .I'll try it also.

Bogdan Simeonov - 7 years ago
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