\(\underline\text{N1L}\quad\boxed{\dot{\mathbf{v}}=0\iff\sum\mathbf{F}=0}\)
N2L‾p˙∝∑F( ⟺ p˙=∑F)\underline\text{N2L}\quad\boxed{\dot{\mathbf{p}}\propto\sum\mathbf{F}\left(\iff\dot{\mathbf{p}}=\sum\mathbf{F}\right)}N2Lp˙∝∑F(⟺p˙=∑F)
N3L‾F12=−F21\underline\text{N3L}\quad\boxed{\mathbf{F}_{12}=-\mathbf{F}_{21}}N3LF12=−F21
Note by Gandoff Tan 1 year, 2 months ago
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Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
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2^{34}
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\sum_{i=1}^3
\sin \theta
\boxed{123}
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