Given a nonisosceles, nonright triangle \(ABC,\) let \(O\) denote the center of its circumscribed circle, and let \(A_1, B_1,\) and \(C_1\) be the midpoints of sides \(BC, CA,\) and \(AB,\) respectively. Point \(A_2\) is located on the ray \(OA_1\) so that \(\triangle OAA_1\) is similar to \(\triangle OA_2A\). Points \(B_2\) and \(C_2\) on rays \(OB_1\) and \(OC_1,\) respectively, are defined similarly. Prove that lines \(AA_2, BB_2,\) and \(CC_2\) are concurrent, i.e. these three lines intersect at a point.
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
...\]
to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
There are no comments in this discussion.