If lucky no. is defined as the no. whose sum of digits is 7, then lucky nos. are in sequence: 7,16,25,34... If 7=A1, 16=A2, 25=A3 and so on; find A65 and A325. (After adding digits once, you cannot add them more times for example:583 is not a lucky no. as you have to add its digits twice to get 7)
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For single digit: 7
For two digits: we have a1a2, where a1+a2=7, 0<a1≤7, 0≤a2<7 which gives 16,25,34,43,52,61,70.
For three digits: we have a1a2a3, where a1+a2+a3=7, 0<a1≤7, 0≤a2,a3<7.
For four digits: we have a1a2a3a4, where a1+a2+a3+a4=7, 0<a1≤7, 0≤a2,a3,a4<7.
For five digits: we have a1a2a3a4a5, where a1+a2+a3+a4+a5=7, 0<a1≤7, 0≤a2,a3,a4,a5<7.
Since 1+7+28<65<1+7+28+84,
A65 must be a four digit number. 65−1−7−28=29.
29−(26+2)=1. So A65 must the smallest four digit number with a1=2.
⇒A65=2005
Similarly 1+7+28+84<325<1+7+28+84+210,
A325 must be a five digit number. 325−1−7−28−84=205. Or 325−1−7−28−84−210=−5
⇒A330=70000
⇒A329=61000
⇒A328=60100
⇒A327=60010
⇒A326=60001
⇒A325=52000