NMTC Inter Level Problem 8

Two sides of a triangle are 88 cm. and 1818 cm. and the bisector of the angle formed by them is of length 6013\frac{60}{13} cm. the length of the third side is

Options:

(A) 2222

(B) 2323

(C) 2424

(D) 2525

#Geometry #NMTC

Note by Nanayaranaraknas Vahdam
6 years, 9 months ago

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1 vote

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Comments

The formula for the bisector of any triangle is l=2abcosθ2a+bl=\frac{2ab \cos\frac{\theta}{2}}{a+b}, where θ\theta is the angle between the sides a,ba,b. Now that you know the cosine of the angle, just use the cosine theorem (also note that cosθ=2cos2θ21\cos \theta = 2\cos^2\frac{\theta}{2}-1).

Using this method we can see that cosθ2=512\cos \frac{\theta}{2}=\frac{5}{12}, thus cosθ=2251441=501441=4772\cos\theta = 2\cdot \frac{25}{144}-1=\frac{50}{144}-1=-\frac{47}{72}, hence by using the cosine theorem we can see that

answer=64+324+2884772=388+447=(C) 24\color{royalblue}{\text{answer}}=\sqrt{64+324+288\cdot \frac{47}{72}}=\sqrt{388+4\cdot 47}=\boxed{(\text{C})\text{ }24}.

mathh mathh - 6 years, 9 months ago

We have the formula of length of angle bisector as derived here

d2=bc(b+c)2((b+c)2a2)d^2=\dfrac{bc}{(b+c)^2} \Bigl( (b+c)^2-a^2\Bigr)

60×6013×13=8×1826×26(262a2)\dfrac{60\times 60}{13\times 13} = \dfrac{8\times 18}{26\times 26} (26^2-a^2)

262a2=60×60×26×2613×13×18×8=10026^2-a^2=\dfrac{60\times 60\times 26\times 26}{13\times 13\times 18\times 8} = 100

This gives a2=576    a=24a^2=576 \implies a=\boxed{24}

Aditya Raut - 6 years, 9 months ago

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What is this formula known as?

Saurabh Mallik - 6 years, 9 months ago

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idk, Length of angle bisector,maybe ! Name is not important, formula is important !

Aditya Raut - 6 years, 9 months ago
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