Note #1: Momentum

This problem is not original and is not intended for public solving

If the surface upon which the block rests is frictionless, find the:

a) impulse b) Δp (change in momentum) c) final momentum d) final velocity


Answers

a) F×Δt=200×5=1000NsF \times Δt = 200 \times 5 = 1000 Ns

b) Δp=FΔt=1000kg m/sΔp = FΔt = 1000 \text{kg m/s} (Δp = impulse)

c) Δp=1000Δp = 1000

initial momentum =mv=50×10=500kg m/s= mv = 50 \times 10 = 500 \text{kg m/s}

final momentum = 1000+500=1500kg m/s1000 + 500 = 1500 \text{kg m/s}

d) p=mvp = mv

1500=50×v1500 = 50 \times v

v=30m/sv = 30 \text{m/s}

Note by Shane Sarosh
1 month, 1 week ago

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1 vote

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Comments

https://www.youtube.com/watch?v=NIVNfI0RN2k ( a yt link for personal reference later :P)

Shane Sarosh - 1 month, 1 week ago

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Hey could you make that link a proper link 🖇️, It is quite hard for users to go on that video. :D

SRIJAN Singh - 3 weeks, 6 days ago
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