Say N is the number we are looking for. Say n is the size of given set. Number of subsets of size r: (rn). Total number of elements in power set given by subsets of size r r×(rn). Hence N=∑r=1nr×(rn).
Say B(x)=(1+x)n.
B(x)=∑r=0n(rn)xr
B′(x)=∑r=1nr×(rn)xr−1
B′(1)=∑r=1nr×(rn)
Hence N=B′(1)
But also B′(x)=n(1+x)n−1
and B′(1)=n(2)n−1
Hence N=n×2n−1
Easy Math Editor
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