Number of elements in a flattened power set

Say NN is the number we are looking for. Say nn is the size of given set. Number of subsets of size r: (nr)\binom{n}{r}. Total number of elements in power set given by subsets of size r r×(nr)r\times\binom{n}{r}. Hence N=r=1nr×(nr)N = \sum_{r=1}^n r \times \binom{n}{r}.

Say B(x)=(1+x)n B(x) = (1+x)^n .

B(x)=r=0n(nr)xrB(x) = \sum_{r=0}^n \binom{n}{r} x^r

B(x)=r=1nr×(nr)xr1B'(x) = \sum_{r=1}^n r\times\binom{n}{r} x^{r-1}

B(1)=r=1nr×(nr)B'(1) = \sum_{r=1}^n r \times \binom{n}{r}

Hence N=B(1)N = B'(1)

But also B(x)=n(1+x)n1B'(x) = n(1+x)^{n-1}

and B(1)=n(2)n1B'(1) = n(2)^{n-1}

Hence N=n×2n1N = n\times2^{n-1}

Note by Ishu Bansal
1 year, 3 months ago

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