Find a number that when divided by the Hardy-Ramanujan taxicab number , it produces a number such that the sum of it's digits is equivalent to a quarter of a power of .
In simplified terms:
such that
The only condition is that as .
You're looking for the first number.
Easy Math Editor
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2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
@Zakir Husain, @Pi Han Goh, @Vinayak Srivastava, @Mahdi Raza, @Aryan Sanghi
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@Yajat Shamji- Is abcd=a×b×c×d or they are digits?
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I think abcd is the four-digit number. Yes, I agree that it might be confusing because the result can be more than a four-digit number, but let him clarify
@Gandoff Tan
As x can be equal to 1729 (∵x≥1729). If x=1729 then a=0,b=0,c=0,d=1;a+b+c+d=1=422 therefore x=1729
17291729=0001=0+0+0+1=1=422
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It is written that 1729x=abcd;a+b+c+d=42n not 1729x=42n
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What is asked is the sum of digits after the division and that is 1
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2.
No. What is asked is that the sum of the digits equals a quarter of a power ofThanks for finding the first number, @Mahdi Raza, @Zakir Husain!
@Mahdi Raza, @Zakir Husain - I am posting Number Spy Challenge 2 in ≤5 minutes! After that, I'll see you tomorrow!