Oh the number of prime factors

I want to know how to prove this statement :

For each positive number $n$ ,there exists two positive number $a,b$ such that :

(1) The number of prime factors of $a$ $\large =$ The number of prime factors of $b$ ;

(2) $n=a-b$ .

When $n$ is even , then take $a=2n$ and $b=n$ . But I failed badly in the case $n$ is odd.

I'd appreciate it if you can help. And thanks for reading!

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Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$