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This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
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Comments
2) Direct using AM GM
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Can you show?and what about 1st?
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Apply am gm on a1&a2, a1&a3,...,a1&an,a2&a3........... Add them all
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@Dev Sharma @Kushagra Sahni @Nihar Mahajan @Surya Prakash @Swapnil Das Adarsh Kumar
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Did 2nd on my own
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Did you also use AM-GM?
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By using A.M−G.M we get
ω=2∑ωa1aω≤(2(n−1)a1+∑ω=2ωaω)
ω=3∑ωa2aω≤(2(n−2)a2+∑ω=3ωaω) . . . aω−1aω≤2aω−1+aω
Adding all above equations we get
I<J∑aIaJ≤2(n−1)(∑ω=1ωaω)
Hence proved !!!
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Thanks but I got it after the hint was dropped by dev. I wanted the hint for 1st question. Can you give me the hints or provide the solution?