One of the hard problems I have ever tackled

A gas of identical H-Like atom has some atoms in the lowest energy level A and somme atoms in a particular upper energy level B and there are no atoms in any other energy level. The atoms of the gas make transition to a higher energy level by absorbing monochromatic light of photon energy 2.7eV.

Subsequently the atoms emit radiation of only six different photon energies...some of the emitted photons have energy 2.7eV Some have more or some have less than 2.7eV. Find the ionisation energy for the gas atoms?

#Chemistry

Easy Math Editor

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Comments

@Ronak Agarwal @Raghav Vaidyanathan @Mvs Saketh @KRISHNA SHANKAR @Manish Dash @Nihar Mahajan @Mehul Arora

sarvesh dubey - 5 years, 12 months ago

Pls tell ur approach when whoever solves this question...

sarvesh dubey - 5 years, 12 months ago

Don't you think that you should have used the term "electrons" instead of "atoms" at some places? @sarvesh dubey

Manish Dash - 5 years, 12 months ago

Yes I thought of it but I presented the question as it was!!! P bahadur chp-3...@Manish Dash

sarvesh dubey - 5 years, 12 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$