Recently I studied the wave equation.Then I read about quantum numbers.Now the quantum number about which I am concerned about is the Azimuthal Quantum number or the orbital angular momentum quantum . Now, can have the values
= 1 , 2 , 3, ........... , (-1)
Now I further read that for orbital = 0 . Again for a single electron magnitude of orbital angular momentum is given by
Now if we put in the above equation we get the magnitude of the orbital angular momentum .i.e., = 0
Means the electron is not at all moving around the nucleus, and still the electron doesn't fall in the nucleus ??
For a while I considered the spin angular momemntum , but it doesn't help in any way.If the electron is fixed at a point , spinning( I know spin does not literraly mean spinning on the axis like the planets.Its an intrinsic property like charge) at a point does not help either.
Further, even spin does affect it, the two electrons in the same orbital have opposite spin which would cancel out(opposite direction).
Hope I get an answer.
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if I am not wrong then - the value of orbital angular momentum = 0 does not describes the velocity of the electron (i.e. it is not moving). But it tells the total magnitude of the "angular momentum" of an electron in an orbital.
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I am afraid you are wrong
Firstly, angular momentum includes velocity as L = r×(mv)
And hence angular momentum describes the velocity too. Second, as you mentioned the total angular momentum is given by the quatum number j which has the values
j = l+s, l+s-1 ,...........|l-s|
And gives the magnitude of TOTAL angular momentum(orbital angular momentum + spin angular momentum) according to the relation
Total angular Momentum = l(l+1) ℏ