This is a proof - based question.
a(n)=(n2+n+1)2+1a(n) = (n^2 + n + 1)^2 + 1a(n)=(n2+n+1)2+1 b(n)=a(1)a(2)+a(1)a(3)a(2)a(4)+⋯+a(1)a(3)⋯a(2n−5)a(2n−3)a(2)a(4)⋯a(2n−4)a(2n−2)+a(1)a(3)⋯a(2n−3)a(2n−1)a(2)a(4)⋯a(2n−2)a(2n)b(n) = \frac{a(1)}{a(2)} + \frac{a(1)a(3)}{a(2)a(4)} + \cdots + \frac{a(1)a(3) \cdots a(2n - 5)a(2n - 3)}{a(2)a(4) \cdots a(2n - 4)a(2n - 2)} + \frac{a(1)a(3) \cdots a(2n - 3)a(2n - 1)}{a(2)a(4) \cdots a(2n - 2)a(2n)}b(n)=a(2)a(1)+a(2)a(4)a(1)a(3)+⋯+a(2)a(4)⋯a(2n−4)a(2n−2)a(1)a(3)⋯a(2n−5)a(2n−3)+a(2)a(4)⋯a(2n−2)a(2n)a(1)a(3)⋯a(2n−3)a(2n−1) Prove that b(n)<12b(n) < \frac{1}{2}b(n)<21.
Note by Thành Đạt Lê 3 years, 5 months ago
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This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
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\sum_{i=1}^3
\sin \theta
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