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Math
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2 \times 3
2×3
2^{34}
234
a_{i-1}
ai−1
\frac{2}{3}
32
\sqrt{2}
2
\sum_{i=1}^3
∑i=13
\sin \theta
sinθ
\boxed{123}
123
Comments
This is an interesting problem, namely because the parabola's axis is not parallel to an x-y axis. We are used to dealing with conics in this form. However, using the definition of a parabola (distance to a point on the parabola is the same from a fixed point called the focus and a fixed line called the directrix), one can develop a hairy formula for a general parabola. Plugging in and solving for some variables, I got a possible focus to be (1,0) and a possible directrix of x-2y=0. The axis of the parabola then must be 2x+y=2, and the vertex (9/10,7/10). There could be more answers, but I didn't check. If you want me to look more into this problem or write a formal proof, I'll consider it.
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
...\]
to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
This is an interesting problem, namely because the parabola's axis is not parallel to an x-y axis. We are used to dealing with conics in this form. However, using the definition of a parabola (distance to a point on the parabola is the same from a fixed point called the focus and a fixed line called the directrix), one can develop a hairy formula for a general parabola. Plugging in and solving for some variables, I got a possible focus to be (1,0) and a possible directrix of x-2y=0. The axis of the parabola then must be 2x+y=2, and the vertex (9/10,7/10). There could be more answers, but I didn't check. If you want me to look more into this problem or write a formal proof, I'll consider it.
your in level four of geometry...please give it a try at least....it does not need much perspiration...best of luck ....:)
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Dude this is already done... but i liked this problem very much that's why posted that..