perimeter ?

a circle whose area is 2/pie.a rectangle inside the circle.then find the parameter of that rectangle.

Note by Google Face
8 years, 1 month ago

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Comments

its 8/pie.....i calculated so..

Anurag Nayan - 8 years, 1 month ago

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yeah 8π\Large \frac{8}{\pi} is correct

Vikram Waradpande - 8 years, 1 month ago

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I think many answers are possible. It's 8/π only when the rectangle is a square, as in a rectangle other than the square the angle made by the two radii by either the length or breadth is not 90 degrees so we can't apply pythagoras theorem here.

Bhargav Das - 8 years, 1 month ago

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@Bhargav Das Yeah I took the rectangle to be a square.

Vikram Waradpande - 8 years, 1 month ago

how please explain

Google Face - 8 years, 1 month ago

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I took the rectangle as a square. If that's not the case, then the problem is lacking some information i guess.

If we consider the rectangle to be a square, then here goes the solution: We have, π×r2=2π    r=2π\large \pi\times r^2=\large \frac{2}{\pi} \implies \boxed {r=\frac{\sqrt{2}}{\pi}} Now, let the side of square be xx. Then 2×x2=8π2    x=2π\large 2\times x^2=\large \frac{8}{\pi^2} \implies x=\large \frac{2}{\pi} This means the perimeter is 4×2π=8π\large 4\times \large \frac{2}{\pi}=\large \boxed {\boxed{\frac{8}{\pi}}}

Vikram Waradpande - 8 years, 1 month ago

I think 8/π is right answer either it is square or rectangle. because in both case both diagonal will be same, because it is diameter of circle. So even by changing length and width of the rectangle parameter will be same in all case. and that can be find by assuming that rectangle as a square..

Bharat Bhawsar - 7 years, 3 months ago
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