Physics- Electricity

The current in a conductor varies as follows: during the first 8 sec there is a linear change from zero to 4 amp; during the next 15 sec the current is constant at 4 amp; during a third period of 20 sec the current decreases linearly to 3 amp. Determine (a) the total charge transferred in the elapsed time of 43 sec, (b) the average current

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Easy Math Editor

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Comments

try drawing the graph of current v/s time. And use the concept the area enclosed by graph with time axis shall give you total charge flown (i.e Ans Part (a) ). Once you've calculated the total charge flown through the conductor, The avg. current is = Total Charge flown/ Total time taken

Rahul Nahata - 7 years, 6 months ago

oh thankyou so much :)

Juverne Arjoy Carandang - 7 years, 6 months ago

The answer must be (a)146C (b)3.395A

Maharnab Mitra - 7 years, 6 months ago

Can you explain to me, how did you get that answers? Thankyou :)

Juverne Arjoy Carandang - 7 years, 6 months ago

how ? explain more plss

Al Jade Abello - 7 years, 6 months ago

hey, this is all about on basic electrical circuits..

Juverne Arjoy Carandang - 7 years, 6 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$