Two identical blocks A and B each of mass M are placed on a long inclined plane (angle of inclination = θ ) with A higher up than B. The coefficients of friction between the plane and the blocks A and B are respectively µ A and µ B with tan θ > µ B > µ A. The two blocks are initially held fixed at a distance d apart. At t = 0 the two blocks are released from rest.
Find the time in which the two blocks collide?
My answer ; -
What about you?Is my answer correct?
I am not sure with my answer, please all of us, lets discuss!
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The two blocks will meet up after a time t such that
d+2g(sin(θ)−μBcos(θ))=2g(sin(θ)−μAcos(θ)),
which when solved for t gives us tc=gcos(θ)(μB−μA)2d.
Suppose μA=μB. Then you wouldn't expect the two blocks to ever meet, but your formula would have them meeting after g2dtan(θ) seconds, while mine would have tC→∞ as expected.
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This seems to be a generalization of that "underkill" problem that was posted recently.
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Exactly. I found it a bit odd at first that cos(θ) was in the denominator, since this would result in a finite tc for θ=0, which doesn't make sense, (although an infinite tc for θ=π/2 does make sense as the two blocks would both be in free-fall so A would never catch up). But then I remembered that we require that
tan(θ)>μB⟹θ>arccos(1+μB21).
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Which underkill problem? Can you please provide the link sir?
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One can generalise further : If the time at which they first meet is t1, the subsequent times of meeting again (after collision) turns out to be odd multiples of t1
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my friends are expecting around 310-315
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I'll take your word for it(if i write advanced)
thank you!
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@Rohith M.Athreya are you giving either of ISI or CMI ?
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II no
Thanks sir!
Even I got the same answer as you sir. :)
@Md Zuhair From where did you get this problem?
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i did a very fine mistake! Its correct now!
@Md Zuhair Yup, my answer matches with the one given by Brian Charlesworth and yes, its correct :-) ! Sorry yours was wrong :-( .
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Ya I got it now
Let me tag some of you,
@Aniket Sanghi , @Rohith M.Athreya , @Ayon Ghosh , @Steven Chase , @Brian Charlesworth!
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http://olympiads.hbcse.tifr.res.in/olympiads/wp-content/uploads/2017/01/INPhO2017-Solution-20170131.pdf