Physics Question

The sliding frictional force between a 4 kg box and the floor is 15 N.It is pushed across the floor with a constant force such that it accelerates at 0.8 m/s(squared) . What is the force applied to the box? A 9.8 N B 18.2 N C 3.6 N D 6.2 N If this same force calculated is applied to the box which is now placed on a completely frictionless floor what is the new acceleration produced? [ in m/s(squared)] A 8.2 B 16.2 C 4.6 D 2.3

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`2 \times 3`	$2 \times 3$
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Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$