Hello everybody! This is my very first note. As the title suggests, today we are going to talk about something related to pi. Nah, not the chicken pie or apple pie or any other pies that you enjoy eating but the pi defined as the ratio of circumference to the diameter of a circle!
Well, to get things started, find without using a calculator. Actually, this is a question which I propose yet fail to solve until now.
More generally, find in terms of .
I hope someone can offer help or suggestions. If you find this interesting just like I do, help me like or re share this note to attract the attention of pros, thank you. I'll sign off here for now.
Cheers!
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2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
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Comments
π=3.14⟹⌊π⌋=3
So, we have to find ⌊π⌋+⌊π2⌋+⌊π3⌋+...+⌊π10⌋
⟹3+32+33+34+35....+310
The above series is in G.P with a=3,r=3,n=10
Sum of terms in G.P = 3−13(310−1)
⟹1.5(310−1)
Coming to the next part of the question sum of infinite terms in an increasing G.P is infinite.
However, if n is finite the formula would be :
3−13(3n−1)
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@Ram Mohith. You can't assume π=3 just like that. For instance, π3=31.000627668 so ⌊π3⌋=31 instead of 33=27. You can verify this with a calculator. The difficult part is that π=3.14159265 and with exponentiation things can get very random.
Interesting question, may use this identity 1+41+91+161+⋯=6π2 to do that but I'm not sure...
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Oh wow. I did not think of this. Thanks for your suggestion.
Take a look at this OEIS ,though it may not be helpful.
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Oh I see. Thanks for your idea
Perhaps utilize 2π=1⋅3⋅3⋅5⋅5⋅7⋅7⋅9⋯2⋅2⋅4⋅4⋅6⋅6⋅8⋅8⋯?
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Wow. Is there a proof for this?
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Wallis Product
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@X X
Thanks