please anyone help me....

a number consist of two digit whose sum is 8. if 18 is added to the number the digits change their places . find the number

Note by Pooja Arora
8 years ago

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2 votes

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Comments

The number is 35.

Siddharth Kumar - 8 years ago

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how??

Pooja Arora - 8 years ago

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pls give me step by step procedure...

Pooja Arora - 8 years ago

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@Pooja Arora xx is the digit at tens place and yy at units place.

x+y=8x+y=8

10x+y+18=10y+x10x+y+18=10y+x

Just solve these equations.

Aditya Parson - 8 years ago

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@Aditya Parson agreed...:)

@Aditya Parson thanku so much.....

Pooja Arora - 8 years ago

@Pooja Arora find the pairs of one-digit numbers whose sum is 8: (1,7),(2,6),(3,5) (1,7),(2,6),(3,5) then the possibilities are 17,26 and 35 by trial and error we get 35

Tan Li Xuan - 8 years ago

let the unit digit be x &tens digit be ythen original no.is10y +x. and 1st equation is x+y =8 and 2nd equation is 10y+x+18=10x+y then from eq.1 x=8-y substituting the value of x in 2nd equation 10y+8-y +18=10(8-y)+y 9y +26=80-10y+y 9y+26=80-9y 9y +9y=80-26 18y=54 y=3 x=8-3=5 no.=10*3+5 35

Nikhil Raj - 8 years ago
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