Please give the answers alongwith solutions

Q1.) Find the sum of n terms:

1/ (4.7.10) + 1/(7.10.13) + 1/(10.13.16) +.............................

Q2.) Find the sum of n terms:

3/(1.2.4) + 4/(2.3.5) + 5/(3.4.6) + ................

Q3) Find the sum of n terms

1/( 1+ 1^2 + 1^4) + 2/(1 +2^2 + 2^4) + 3/(1 +3 ^2 + 3^4 ) + ..........

Q4) Find the sum of n terms:

6+13+22+33+.......................

Q5) Find the sum of n terms:

2+5+14+41+122.................

Q6) Find the sum of n terms: 3^2 + 7^2 + 11^2 +.................

#TelescopingSeries #Progressions

Easy Math Editor

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Comments

I Can Help You In Them After NTSE As I Dont Have Much time to spend on brilliant. but still for 3rd problem you can factorize the denominator as follows and then apply telescoping sum a^4+a^2+1 = (a^2+a+1)(a^2-a+1) for 6th one you can write general term of the progression and apply sigma notation for rest please wait till 10th may i will surely help you after that

Prakhar Bindal - 6 years, 1 month ago

All the best to you for NTSE @Prakhar Bindal . By the way, I am also going to appear NTSE on 10th MAY

Manish Dash - 6 years, 1 month ago

Thanks i will surely help you on sunday with all the solutions and all the best to you too!!

Prakhar Bindal - 6 years, 1 month ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$