Please Help!

Two blocks $A$ and $B$ of same mass $M$ are connected with each other with an ideal string of length $2l$ passing over an ideal pulley. The block $A$ is connected to a light pan $C$ with an ideal string as shown in figure. A particle of mass $\frac{M}{2}$ is dropped on pan from height $\frac{l}{2}$ as shown. If collision between particle and pan is plastic, acceleration of $B$ just after the collision is?

Ans is $\frac{g}{9}$ .

Is this solution correct?

#Forces #Mechanics

Easy Math Editor

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Comments

@Raghav Vaidyanathan @Tanishq Varshney @Kushal Patankar Help!

Nishant Rai - 6 years, 1 month ago

@satvik pandey i have made a note on this problem inviting views of other brilliant members(bc now even i am confused :/ )

Nishant Rai - 6 years, 1 month ago

Thanks for making it! :)

satvik pandey - 6 years, 1 month ago

Why wasn't $T_1$ impulsive.😓

Kyle Finch - 6 years, 1 month ago

Can you please post the solution to Angular width of Refracted Beam!

Raghav Vaidyanathan

Nishant Rai - 6 years, 1 month ago

@Raghav Vaidyanathan

Nishant Rai - 6 years, 1 month ago

Raghav Vaidyanathan - 6 years, 1 month ago

@Raghav Vaidyanathan – Could you please explain this answer?

satvik pandey - 6 years, 1 month ago

@Nishant Rai

Although your answer is correct, the FBDs that you have drawn are not. You have missed out the gravitational force on $A$ . Due to this reason, you have skipped using $T_1 -Mg=Ma$

In reality, at the moment the mass strikes the pan:

$T_1 = Mg + M\frac {v^2}{l}$

And hence: $T_1 -Mg=Ma=M\frac {v^2}{l}$

Otherwise, you can also use constraint relations to get to same result.

Raghav Vaidyanathan - 6 years, 1 month ago

@satvik pandey

Raghav Vaidyanathan - 6 years, 1 month ago

Raghav Vaidyanathan

i have done the same thing, (this solution is not mine, this question came in mock paper of some coaching institute, they have provided this solution)

Nishant Rai - 6 years, 1 month ago

Okay, but they aren't fully wrong, we can get everything without FBD itself...

Raghav Vaidyanathan - 6 years, 1 month ago

@Raghav Vaidyanathan – btw you are appearing for JEE ? are you enrolled in any coaching institute?

Nishant Rai - 6 years, 1 month ago

@Nishant Rai – Yes, FIITJEE

Raghav Vaidyanathan - 6 years, 1 month ago

I have a confusion. I think it is assumed that just after the collision block A performs a circular motion. But as soon as the block a A gets a tangential velocity it would have centripetal as well as a radial acceleration. How can we ignore that?

satvik pandey - 6 years, 1 month ago

I think you guys would like to see this discussion.

satvik pandey - 6 years ago

My Answer is a little different..

Rohit Gupta - 6 years ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$