Please help me to solve this geometry problem

PQRPQR is an isosceles triangle where PQ=PRPQ = PR. XX is a point on the circumcircle of PQR\triangle PQR, such that it being in the opposite region of PP with respect to QRQR. The normal drawn from the point PP on XRXR intersects XRXR at point YY. If XY=10XY = 10 , then find the value of QX+RXQX + RX.

#Geometry

Note by Ashraful Mahin
4 years, 6 months ago

No vote yet
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Comments

What have you tried?

Have you drawn a diagram? If so, what does it look like?

Calvin Lin Staff - 4 years, 6 months ago

its easy. extend XR to a point M such that RM=QX. Now try proving that Y is the mid point of XM.

Aditya Kumar - 4 years, 4 months ago

Ahmad Saad - 4 years, 1 month ago
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