If in a box there are 3 blue balls, 4 red balls, 7 yellow balls and 2 green balls, then how many times we have to take a ball at random so that we would get 2 balls of the same color?
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I think your question needs editing, it should rather be "how many minimum no. of balls one needs to pick to assure that he gets atleast 2 balls of the same colour". Then the answer would be 5 using PHP.
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This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
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to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
I think your question needs editing, it should rather be "how many minimum no. of balls one needs to pick to assure that he gets atleast 2 balls of the same colour". Then the answer would be 5 using PHP.
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i don't know, i just write the original question. but thanks!:)
5 . Because if we need 4 chances to pick a ball of every colour then another chance will surely be the second ball of any colour.
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Thanks:D
If the problem is on expectation, I get 49212 balls to be picked on average.
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Sorry, my above answer is a blunder! I find the expectation to be 27308741