Please remember euler

$e^{i \pi } + 1 = 0$

is the great equation given by “EULER”.

#Algebra

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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

Can you prove it?

Isaac Buckley - 5 years, 5 months ago

You can see the brilliant wiki on this.

Satyajit Ghosh - 5 years, 5 months ago

Please provide a link .

Raven Herd - 5 years, 5 months ago

Complex number can be exponentially expressed as e^ix =cosx+isinx

Therefore
e^ipi=cos(pi)+i sin(pi)

Since sin(pi)=0 Cos(pi)=-1

the above equation

e^i(pi)+1. => -1+1. => 0

Hemanth Koundinya - 5 years, 5 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$